Relationship of Pointers with Arrays

The name of the array is the implicit pointer to the first variable of array.  For example, for an array arr[5],

arr=&arr[0]

arr+1=&arr[1]

….

Arr+4=&arr[4]

//example code comparing address of array with its implicit pointers

#include

int main () {

   int  var[] = {10, 100, 200};

    for ( int i = 0; i < 3; i++)

    {

        if((var+i)==&var[i])

            printf(“nTRUE”);

    }

   return 0;

}

//Example code showing how array name can work as pointer

#include

int main () {

   int  var[] = {10, 100, 200};

   for ( int i = 0; i < 3; i++)

    {

      printf(“Address of var[%d] = %xn”, i, var+i );

      printf(“Value of var[%d] = %dn”, i, *(var+i) );

   }

   return 0;

}

Array of Pointers

It is also possible to create an array of pointers and again each pointer is pointing to individual elements of an array.  The following example code giving that scenario.

//example code showing how array of pointers can be created

#include

int main () {

   int  arr[] = {10, 100, 200};

   int *pa[3];  //array of pointers

    for ( int i = 0; i < 3; i++)

    {

        pa[i]=&arr[i];

    }

    for ( int i = 0; i < 3; i++)

    {

        printf(“naddress of arr[%d] is : %d”,i,pa[i]);

        printf(“nvalue at arr[%d] is : %d”,i,*(pa[i]));

    }

   return 0;

}